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问题: 21. 当n为自然数时,有x^6n+1/x^6n=2 '

21. 当n为自然数时,有x^6n+1/x^6n=2
证明:(1)x+1/x=-1 ==>x^6n+1/x^6n=2
(2)x+1/x=1 ==>x^6n+1/x^6n=2

22.证明:(1)a^2+b^2+c^2+d^2-ab-bc-cd-da=0 ==>a=b=c=d
(2)a^4+b^4+c^4+d^4-4abcd=0 ==>a=b=c=d

解答:

21.这个错了吧,应该是x+1/x=-2 ==>x^6n+1/x^6n=2
证明:x^6n+1/x^6n=2 移项,分解为(x^3n-1/x^3n)^2=0
可以知道x=1或者x=-1,当x+1/x=-2 时,x=-1可得到 x^6n+1/x^6n=2
22.(1)a^2+b^2+c^2+d^2-ab-bc-cd-da=0 ==>2(a^2+b^2+c^2+d^2-ab-bc-cd-da)=0 ==>(a-b)^2+(b-c)^2+(c-d)^2+(a-d)^2=0
==>a=b=c=d
(2)这个要补充条件:a,b,c,d都是正数
证明:a^4+b^4+c^4+d^4-4abcd=0 ==>(a^4-2a^2b^2+b^4)
+(c^4-2c^2d^2+d^4)+(2a^2b^2-4abcd+2c^2d^2)=0
==>(a^2-b^2)^2+(c^2-d^2)^2+2(ab-cd)^2=0
==>a^2=b^2=c^2=d^2当a,b,c,d符号相同时结论成立.