问题: 对数的运算
log37*log29*log49a=log4(1/2),a=???
解答:
log(3)7 * log(2)9 * log(49)a = log(4)(1/2)
<==> (lg7/lg3) * (lg9/lg2) * (lga/lg49) = lg(1/2)/lg4
<==> (lg7/lg3) * (2lg3/lg2) * (lga/2lg7) = -lg2/2lg2
<==> lga/lg2 = -1/2
<==> lga = (-1/2)lg2
<==> lga = lg[2^(-1/2)]
<==> a = 2^(-1/2)
<==> a = 1/√2
<==> a = (√2)/2
版权及免责声明
1、欢迎转载本网原创文章，转载敬请注明出处：侨谊留学（www.goesnet.org）；
2、本网转载媒体稿件旨在传播更多有益信息，并不代表同意该观点，本网不承担稿件侵权行为的连带责任；
3、在本网博客/论坛发表言论者，文责自负。
