17pi/12<x<7pi/4--->5pi/4<pi/4+x<2pi
cos(pi/4+x)=3/5--->sin(pi/4+x)=-4/5,tan(pi/4+x)=-4/3
[sin2x+2(sinx)^2]/(1-tanx)
=2sinxcosx(1+sinx/cosx)/(1-tanx)
=sin2x(1+tanx)/(1-tanx)
=-cos(pi/2+2x)tan(pi/4+x)
=-cos[2(pi/4+x)]tan(pi/4+x)
=-{2[cos(pi/4+x)]^2-1}tan(pi/4+x)
=-[2(3/5)^2-1](-4/3)
=(18/25-1)(4/3)
=-28/75.
