问题: 一道八年级题
如图
解答:
(x+3)/(x+2) = 1/(√2+1)
--->(x+2)/(x+3) = 1-1/(x+3) = √2+1
--->1/(x+3)=-√2
--->x+3 = -1/√2
[(x-3)/(2x-4)]÷[5/(x-2)-(x+2)]
= (x-3)÷[10-2(x+2)(x-2)]
= 2(9-x²)/(x-3)
= -2(x+3)
= √2
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