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问题: 高三数学题

1.tan(α+β+180/6)=1/2,tan(β-180/6)=-1/3,tan(α+180/3)=

解答:

tan(α+180/3) = tan[(α+β+180/6)-(β-180/6)]
= [(1/2)-(-1/3)]/[1+(1/2(-1/3)] = 1