问题: 指数函数
化简：
解答:
x-1 =[x^(1/3)-1][x^(2/3)+x^(1/3)+1]
x+1 =[x^(1/3)+1][x^(2/3)-x^(1/3)+1]
x-x^(1/3) =[x^(1/3)+1][x^(1/3)-1]x^(1/3)
原式 =[x^(1/3)-1]+[x^(2/3)-x^(1/3)+1]-[x^(1/3)+1]*x^(1/3)
= -x^(1/3)
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