问题: 解三角函数
20度40度60度80度的正弦相乘,请问怎么解?
解答:
2sinasinb=cos(a-b)-cos(a+b)
2sinacosb=sin(a+b)+sin(a-b)
上述公式很容易用和差公式推导
sin20°sin40°sin60°sin80°
=[cos(20°-40°)-cos(20°+40°)]sin80°sin60°/2
=(cos20°sin80°-cos60°sin80°)sin60°/2
={[sin(20°+80°)+sin(80°-20°)]/2-sin80°/2}sin60°/2
={[sin100°+sin60°]/2-sin80°/2}sin60°/2
={sin80°/2+sin60°/2-sin80/2}sin60°/2
=sin60°/2*sin60°/2
=3/16
版权及免责声明
1、欢迎转载本网原创文章,转载敬请注明出处:侨谊留学(www.goesnet.org);
2、本网转载媒体稿件旨在传播更多有益信息,并不代表同意该观点,本网不承担稿件侵权行为的连带责任;
3、在本网博客/论坛发表言论者,文责自负。