首页 > 留学知识库

问题: lim

lim[(1+1/2)(1+1/2^2)(1+1/2^4)...(1+1/2^2n)]=?
n→∞

解答:

lim[(1+1/2)(1+1/2^2)(1+1/2^4)...(1+1/2^2n)]=
n→∞
lim[2*(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)...(1+1/2^2n)]=
n→∞
lim[2(1-1/2^2)(1+1/2^2)(1+1/2^4)...(1+1/2^2n)]=
n→∞
lim[2(1-1/2^4)(1+1/2^4)...(1+1/2^2n)]=
n→∞
....................................=

lim[2(1-1/2^4n)]=
n→∞
2*(1-0)=2