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问题: 初一数学1道

32(x-y)的四次方/[-8/9(y-x)的三次方]

解答:

32(x-y)^4/[-8/9(y-x)^3]
=32(x-y)^4/[8/9(x-y)^3]
=32*(9/8)(x-y)
=36(x-y)