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问题: 高一数学题(三角函数)

sin50(1+√3tan10)

解答:

sin50(1+√3tan10)
=sin50(1+tan60tan10)
=sin50(cos60*cos10+sin60sin10)/cos60cos10
=2sin50*cos50/cos10
=sin100/cos10
=sin(90+10)/cos10
=cos10/cos10
=1