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问题: 解lg^2+lg2lg50-lg2+根号下[(lg5-1)^2]

解答:

lg^2(5)+lg2lg50-lg2+√[(lg5-1)^2] =
lg^2(5)+lg2lg(2*5^2)-lg2+√[(1-lg5)^2] =
[lg^2(5)+lg^2(2)+2lg2lg5]-lg2+(1-lg5)=
[(lg2+lg5)^2]]-lg2+(1-lg5)=
[lg(2*5)]^2]-lg2+(1-lg5)=
1-lg2+1-lg5=
2-(lg5+lg2)=
2-lg10=
2-1=
1